3[7-2(j-8)]=4(4j+2)

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Solution for 3[7-2(j-8)]=4(4j+2) equation:


Simplifying
3[7 + -2(j + -8)] = 4(4j + 2)

Reorder the terms:
3[7 + -2(-8 + j)] = 4(4j + 2)
3[7 + (-8 * -2 + j * -2)] = 4(4j + 2)
3[7 + (16 + -2j)] = 4(4j + 2)

Combine like terms: 7 + 16 = 23
3[23 + -2j] = 4(4j + 2)
[23 * 3 + -2j * 3] = 4(4j + 2)
[69 + -6j] = 4(4j + 2)

Reorder the terms:
69 + -6j = 4(2 + 4j)
69 + -6j = (2 * 4 + 4j * 4)
69 + -6j = (8 + 16j)

Solving
69 + -6j = 8 + 16j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-16j' to each side of the equation.
69 + -6j + -16j = 8 + 16j + -16j

Combine like terms: -6j + -16j = -22j
69 + -22j = 8 + 16j + -16j

Combine like terms: 16j + -16j = 0
69 + -22j = 8 + 0
69 + -22j = 8

Add '-69' to each side of the equation.
69 + -69 + -22j = 8 + -69

Combine like terms: 69 + -69 = 0
0 + -22j = 8 + -69
-22j = 8 + -69

Combine like terms: 8 + -69 = -61
-22j = -61

Divide each side by '-22'.
j = 2.772727273

Simplifying
j = 2.772727273

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